To solve for s, take an inner product of both sides of Eq. (4-108) with -i-oA,
exploiting the fact that A UoA = -1 and that noK)UoA 0. Then
TEN s +0 {XA [+BjCjDS3 + 3ACDS2 (AAK)
TFN -S -oA A BC, D6 BC 3DC 0D 2 0 (K)
1 0o
+3S (K)i K) (nLAL) + (<)A) ( ) 7() on(M)A )
I l^B L0 -D E N^ I
+ (K) ) K(o(L)A) L(n AM) (M (N)A) }
+0[(s, A)5/74]. (4-109)
To solve for A', take an inner product of both sides of Eq. (4-108) with nl ,
exploiting the fact that uAnA =- 0 and that A (I^A = K. Then
o oA oAo( K. Then
F N A CoA Do BC D 3 0CD 2 0 aB(K)
+3jS (K K) (L) A m) Am)
2 C,DE 0B C D 4 uCu D E 3 B(K)
+1 BC,DE o oKuoo +4uouoo (o)A)
6DjE 2 (B K ) C L
+6u0 0 ((K)A L) (noL (M)A
+4fB K)AC L )AD )AM)
+ (K)A ( L)A) (Ln AM) (