Fdrag
L
Internal pressure, P
Figure 2.4 Drag loading assumed as a distributed force
x x
2 2
wx
M
tA
4 V
wL
2
Figure 2.5 Free body diagram of beam section
+ MA = wL )x + (wx) +M = 0 (2.12)
M(x) = w(Lx- x2) (2.13)
2
2.3.2 Vertical Deflection
To solve for beam deflections, the specific moment equation, Equation 2.13, is
substituted into Equation 2.11 and integrated twice, yielding Equations 2.14 through 2.16.
d2y w
d y (Lx x2) (2.14)
dxC2 2E* mr3