- 150 - The temperature distribution is obtained by using numerical methods to solve equation (8.49). This equation is first written in the form K _1 R K d2T F - idT R 3 dKR 11dT R (8.51) dr2 dr KRR dT 'drJ l6(T5 The temperature gradient is evaluated over the interval [0, RI as follows: (ITr dT (.2 (r) = F(r')dr' + d( (.52) 0 The temperature distribution over [0, R] is then given by jrdl-rr) d 8.3 T(r) = (T dr' + T(0) (8.53) dT using the values from (8.52) for d-i(r'). In order to dT obtain values for jr using (8.52), F(r) must be initially evaluated at r = 0. From (8.51), the first term of F(0) appears to be undefined since limI rda) = an inder+0 terminate form. To eliminate this computational difficulty, r is replaced by r + s0 when r&[0,s&0], where s0 is an arbitrarily small positive constant. This allows the numerical integration to begin at r = 0 since the first term of F(0) becomes