- 110 -


where the symbols are defined as in Chapter V. To simplify the notation, let


N01 = NH   N02 = NH, N03 = NH+, N04 = NH-, N05 = NH+
        2                                          2

                                                   (6.6)

Dividing both sides of (6.2) through (6.5) by the total particle density, NTOT, gives


   d2
     2  K
   d 1   01
   1

d3C d3 Ce  K K, d2      02


d2 C
   d     03



ds Ce    *
    d   K0


(6.7) (6.8) (6.9) (6.10)


where


     Ce = Ne/N TOT and d. = Noi/NTOT, i = 1, 2, . . ., 5

                                                   (6.11)


The uranium equilibrium reactions are


U0  -_ U1+ + +  -     + e U1   U2++ e