k -k. k A. Now suppose that a new row is added. The number of columns becomes: U.+A.-L.+k -k Ck+1 + 1 3-4 1 = k + so there is a new column which can be assigned as the output for the new row. Theorem 3-1 is proved. Corollary: It is always possible to specify the index outputs as offsets from the index values in an IDM. Proof: For the list choose any list element as the index output offset. For the range note that for L.=U. the output can be expressed as an 7 1 offset from the function index value, say k Now assume that for L.